3.330 \(\int \cos ^7(c+d x) (a+i a \tan (c+d x))^{7/2} \, dx\)

Optimal. Leaf size=196 \[ \frac {i a^{7/2} \tanh ^{-1}\left (\frac {\sqrt {a} \sec (c+d x)}{\sqrt {2} \sqrt {a+i a \tan (c+d x)}}\right )}{8 \sqrt {2} d}-\frac {i a^3 \cos (c+d x) \sqrt {a+i a \tan (c+d x)}}{8 d}-\frac {i a^2 \cos ^3(c+d x) (a+i a \tan (c+d x))^{3/2}}{12 d}-\frac {i \cos ^7(c+d x) (a+i a \tan (c+d x))^{7/2}}{7 d}-\frac {i a \cos ^5(c+d x) (a+i a \tan (c+d x))^{5/2}}{10 d} \]

[Out]

1/16*I*a^(7/2)*arctanh(1/2*sec(d*x+c)*a^(1/2)*2^(1/2)/(a+I*a*tan(d*x+c))^(1/2))/d*2^(1/2)-1/8*I*a^3*cos(d*x+c)
*(a+I*a*tan(d*x+c))^(1/2)/d-1/12*I*a^2*cos(d*x+c)^3*(a+I*a*tan(d*x+c))^(3/2)/d-1/10*I*a*cos(d*x+c)^5*(a+I*a*ta
n(d*x+c))^(5/2)/d-1/7*I*cos(d*x+c)^7*(a+I*a*tan(d*x+c))^(7/2)/d

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Rubi [A]  time = 0.29, antiderivative size = 196, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 3, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.115, Rules used = {3490, 3489, 206} \[ -\frac {i a^2 \cos ^3(c+d x) (a+i a \tan (c+d x))^{3/2}}{12 d}-\frac {i a^3 \cos (c+d x) \sqrt {a+i a \tan (c+d x)}}{8 d}+\frac {i a^{7/2} \tanh ^{-1}\left (\frac {\sqrt {a} \sec (c+d x)}{\sqrt {2} \sqrt {a+i a \tan (c+d x)}}\right )}{8 \sqrt {2} d}-\frac {i \cos ^7(c+d x) (a+i a \tan (c+d x))^{7/2}}{7 d}-\frac {i a \cos ^5(c+d x) (a+i a \tan (c+d x))^{5/2}}{10 d} \]

Antiderivative was successfully verified.

[In]

Int[Cos[c + d*x]^7*(a + I*a*Tan[c + d*x])^(7/2),x]

[Out]

((I/8)*a^(7/2)*ArcTanh[(Sqrt[a]*Sec[c + d*x])/(Sqrt[2]*Sqrt[a + I*a*Tan[c + d*x]])])/(Sqrt[2]*d) - ((I/8)*a^3*
Cos[c + d*x]*Sqrt[a + I*a*Tan[c + d*x]])/d - ((I/12)*a^2*Cos[c + d*x]^3*(a + I*a*Tan[c + d*x])^(3/2))/d - ((I/
10)*a*Cos[c + d*x]^5*(a + I*a*Tan[c + d*x])^(5/2))/d - ((I/7)*Cos[c + d*x]^7*(a + I*a*Tan[c + d*x])^(7/2))/d

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 3489

Int[sec[(e_.) + (f_.)*(x_)]/Sqrt[(a_) + (b_.)*tan[(e_.) + (f_.)*(x_)]], x_Symbol] :> Dist[(-2*a)/(b*f), Subst[
Int[1/(2 - a*x^2), x], x, Sec[e + f*x]/Sqrt[a + b*Tan[e + f*x]]], x] /; FreeQ[{a, b, e, f}, x] && EqQ[a^2 + b^
2, 0]

Rule 3490

Int[((d_.)*sec[(e_.) + (f_.)*(x_)])^(m_.)*((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[(b*(d
*Sec[e + f*x])^m*(a + b*Tan[e + f*x])^n)/(a*f*m), x] + Dist[a/(2*d^2), Int[(d*Sec[e + f*x])^(m + 2)*(a + b*Tan
[e + f*x])^(n - 1), x], x] /; FreeQ[{a, b, d, e, f}, x] && EqQ[a^2 + b^2, 0] && EqQ[m/2 + n, 0] && GtQ[n, 0]

Rubi steps

\begin {align*} \int \cos ^7(c+d x) (a+i a \tan (c+d x))^{7/2} \, dx &=-\frac {i \cos ^7(c+d x) (a+i a \tan (c+d x))^{7/2}}{7 d}+\frac {1}{2} a \int \cos ^5(c+d x) (a+i a \tan (c+d x))^{5/2} \, dx\\ &=-\frac {i a \cos ^5(c+d x) (a+i a \tan (c+d x))^{5/2}}{10 d}-\frac {i \cos ^7(c+d x) (a+i a \tan (c+d x))^{7/2}}{7 d}+\frac {1}{4} a^2 \int \cos ^3(c+d x) (a+i a \tan (c+d x))^{3/2} \, dx\\ &=-\frac {i a^2 \cos ^3(c+d x) (a+i a \tan (c+d x))^{3/2}}{12 d}-\frac {i a \cos ^5(c+d x) (a+i a \tan (c+d x))^{5/2}}{10 d}-\frac {i \cos ^7(c+d x) (a+i a \tan (c+d x))^{7/2}}{7 d}+\frac {1}{8} a^3 \int \cos (c+d x) \sqrt {a+i a \tan (c+d x)} \, dx\\ &=-\frac {i a^3 \cos (c+d x) \sqrt {a+i a \tan (c+d x)}}{8 d}-\frac {i a^2 \cos ^3(c+d x) (a+i a \tan (c+d x))^{3/2}}{12 d}-\frac {i a \cos ^5(c+d x) (a+i a \tan (c+d x))^{5/2}}{10 d}-\frac {i \cos ^7(c+d x) (a+i a \tan (c+d x))^{7/2}}{7 d}+\frac {1}{16} a^4 \int \frac {\sec (c+d x)}{\sqrt {a+i a \tan (c+d x)}} \, dx\\ &=-\frac {i a^3 \cos (c+d x) \sqrt {a+i a \tan (c+d x)}}{8 d}-\frac {i a^2 \cos ^3(c+d x) (a+i a \tan (c+d x))^{3/2}}{12 d}-\frac {i a \cos ^5(c+d x) (a+i a \tan (c+d x))^{5/2}}{10 d}-\frac {i \cos ^7(c+d x) (a+i a \tan (c+d x))^{7/2}}{7 d}+\frac {\left (i a^4\right ) \operatorname {Subst}\left (\int \frac {1}{2-a x^2} \, dx,x,\frac {\sec (c+d x)}{\sqrt {a+i a \tan (c+d x)}}\right )}{8 d}\\ &=\frac {i a^{7/2} \tanh ^{-1}\left (\frac {\sqrt {a} \sec (c+d x)}{\sqrt {2} \sqrt {a+i a \tan (c+d x)}}\right )}{8 \sqrt {2} d}-\frac {i a^3 \cos (c+d x) \sqrt {a+i a \tan (c+d x)}}{8 d}-\frac {i a^2 \cos ^3(c+d x) (a+i a \tan (c+d x))^{3/2}}{12 d}-\frac {i a \cos ^5(c+d x) (a+i a \tan (c+d x))^{5/2}}{10 d}-\frac {i \cos ^7(c+d x) (a+i a \tan (c+d x))^{7/2}}{7 d}\\ \end {align*}

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Mathematica [A]  time = 1.88, size = 131, normalized size = 0.67 \[ -\frac {i a^3 e^{-i (c+d x)} \left (298 e^{2 i (c+d x)}+188 e^{4 i (c+d x)}+81 e^{6 i (c+d x)}+15 e^{8 i (c+d x)}-105 \sqrt {1+e^{2 i (c+d x)}} \tanh ^{-1}\left (\sqrt {1+e^{2 i (c+d x)}}\right )+176\right ) \sqrt {a+i a \tan (c+d x)}}{1680 d} \]

Antiderivative was successfully verified.

[In]

Integrate[Cos[c + d*x]^7*(a + I*a*Tan[c + d*x])^(7/2),x]

[Out]

((-1/1680*I)*a^3*(176 + 298*E^((2*I)*(c + d*x)) + 188*E^((4*I)*(c + d*x)) + 81*E^((6*I)*(c + d*x)) + 15*E^((8*
I)*(c + d*x)) - 105*Sqrt[1 + E^((2*I)*(c + d*x))]*ArcTanh[Sqrt[1 + E^((2*I)*(c + d*x))]])*Sqrt[a + I*a*Tan[c +
d*x]])/(d*E^(I*(c + d*x)))

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fricas [A]  time = 0.58, size = 258, normalized size = 1.32 \[ \frac {105 \, \sqrt {\frac {1}{2}} \sqrt {-\frac {a^{7}}{d^{2}}} d \log \left (\frac {{\left (i \, a^{4} + \sqrt {2} \sqrt {\frac {1}{2}} \sqrt {-\frac {a^{7}}{d^{2}}} {\left (d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}\right )} e^{\left (-i \, d x - i \, c\right )}}{4 \, d}\right ) - 105 \, \sqrt {\frac {1}{2}} \sqrt {-\frac {a^{7}}{d^{2}}} d \log \left (\frac {{\left (i \, a^{4} - \sqrt {2} \sqrt {\frac {1}{2}} \sqrt {-\frac {a^{7}}{d^{2}}} {\left (d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}\right )} e^{\left (-i \, d x - i \, c\right )}}{4 \, d}\right ) + \sqrt {2} {\left (-15 i \, a^{3} e^{\left (8 i \, d x + 8 i \, c\right )} - 81 i \, a^{3} e^{\left (6 i \, d x + 6 i \, c\right )} - 188 i \, a^{3} e^{\left (4 i \, d x + 4 i \, c\right )} - 298 i \, a^{3} e^{\left (2 i \, d x + 2 i \, c\right )} - 176 i \, a^{3}\right )} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}}{1680 \, d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^7*(a+I*a*tan(d*x+c))^(7/2),x, algorithm="fricas")

[Out]

1/1680*(105*sqrt(1/2)*sqrt(-a^7/d^2)*d*log(1/4*(I*a^4 + sqrt(2)*sqrt(1/2)*sqrt(-a^7/d^2)*(d*e^(2*I*d*x + 2*I*c
) + d)*sqrt(a/(e^(2*I*d*x + 2*I*c) + 1)))*e^(-I*d*x - I*c)/d) - 105*sqrt(1/2)*sqrt(-a^7/d^2)*d*log(1/4*(I*a^4
- sqrt(2)*sqrt(1/2)*sqrt(-a^7/d^2)*(d*e^(2*I*d*x + 2*I*c) + d)*sqrt(a/(e^(2*I*d*x + 2*I*c) + 1)))*e^(-I*d*x -
I*c)/d) + sqrt(2)*(-15*I*a^3*e^(8*I*d*x + 8*I*c) - 81*I*a^3*e^(6*I*d*x + 6*I*c) - 188*I*a^3*e^(4*I*d*x + 4*I*c
) - 298*I*a^3*e^(2*I*d*x + 2*I*c) - 176*I*a^3)*sqrt(a/(e^(2*I*d*x + 2*I*c) + 1)))/d

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giac [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^7*(a+I*a*tan(d*x+c))^(7/2),x, algorithm="giac")

[Out]

Timed out

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maple [B]  time = 1.77, size = 1260, normalized size = 6.43 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(d*x+c)^7*(a+I*a*tan(d*x+c))^(7/2),x)

[Out]

-1/107520/d*(105*I*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(13/2)*arctanh(1/2*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(1/2)*sin(
d*x+c)/cos(d*x+c)*2^(1/2))*cos(d*x+c)^6*sin(d*x+c)*2^(1/2)+630*I*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(13/2)*arctanh
(1/2*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(1/2)*sin(d*x+c)/cos(d*x+c)*2^(1/2))*cos(d*x+c)^5*sin(d*x+c)*2^(1/2)+18432
*sin(d*x+c)*cos(d*x+c)^11-7168*sin(d*x+c)*cos(d*x+c)^9+8960*sin(d*x+c)*cos(d*x+c)^8+6144*sin(d*x+c)*cos(d*x+c)
^10-13440*sin(d*x+c)*cos(d*x+c)^7+122880*I*cos(d*x+c)^14-61440*I*cos(d*x+c)^13-79872*I*cos(d*x+c)^12+24576*I*c
os(d*x+c)^11+1024*I*cos(d*x+c)^10+1792*I*cos(d*x+c)^9+4480*I*cos(d*x+c)^8-13440*I*cos(d*x+c)^7-122880*sin(d*x+
c)*cos(d*x+c)^13+61440*sin(d*x+c)*cos(d*x+c)^12+1575*I*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(13/2)*arctanh(1/2*(-2*c
os(d*x+c)/(1+cos(d*x+c)))^(1/2)*sin(d*x+c)/cos(d*x+c)*2^(1/2))*cos(d*x+c)^4*sin(d*x+c)*2^(1/2)+2100*I*(-2*cos(
d*x+c)/(1+cos(d*x+c)))^(13/2)*arctanh(1/2*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(1/2)*sin(d*x+c)/cos(d*x+c)*2^(1/2))*
cos(d*x+c)^3*sin(d*x+c)*2^(1/2)+1575*I*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(13/2)*arctanh(1/2*(-2*cos(d*x+c)/(1+cos
(d*x+c)))^(1/2)*sin(d*x+c)/cos(d*x+c)*2^(1/2))*cos(d*x+c)^2*sin(d*x+c)*2^(1/2)+630*I*(-2*cos(d*x+c)/(1+cos(d*x
+c)))^(13/2)*arctanh(1/2*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(1/2)*sin(d*x+c)/cos(d*x+c)*2^(1/2))*cos(d*x+c)*sin(d*
x+c)*2^(1/2)-105*2^(1/2)*arctan(1/2*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(1/2)*2^(1/2))*(-2*cos(d*x+c)/(1+cos(d*x+c)
))^(13/2)*sin(d*x+c)-105*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(13/2)*arctan(1/2*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(1/2)
*2^(1/2))*sin(d*x+c)*cos(d*x+c)^6*2^(1/2)-630*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(13/2)*arctan(1/2*(-2*cos(d*x+c)/
(1+cos(d*x+c)))^(1/2)*2^(1/2))*sin(d*x+c)*cos(d*x+c)^5*2^(1/2)-1575*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(13/2)*arct
an(1/2*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(1/2)*2^(1/2))*sin(d*x+c)*cos(d*x+c)^4*2^(1/2)-2100*(-2*cos(d*x+c)/(1+co
s(d*x+c)))^(13/2)*arctan(1/2*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(1/2)*2^(1/2))*sin(d*x+c)*cos(d*x+c)^3*2^(1/2)-157
5*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(13/2)*arctan(1/2*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(1/2)*2^(1/2))*sin(d*x+c)*co
s(d*x+c)^2*2^(1/2)-630*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(13/2)*arctan(1/2*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(1/2)*2
^(1/2))*sin(d*x+c)*cos(d*x+c)*2^(1/2)+105*I*2^(1/2)*arctanh(1/2*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(1/2)*sin(d*x+c
)/cos(d*x+c)*2^(1/2))*(-2*cos(d*x+c)/(1+cos(d*x+c)))^(13/2)*sin(d*x+c))*(a*(I*sin(d*x+c)+cos(d*x+c))/cos(d*x+c
))^(1/2)/(I*sin(d*x+c)+cos(d*x+c)-1)/cos(d*x+c)^6*a^3

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maxima [B]  time = 1.06, size = 1250, normalized size = 6.38 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^7*(a+I*a*tan(d*x+c))^(7/2),x, algorithm="maxima")

[Out]

1/6720*((-140*I*sqrt(2)*a^3*cos(3/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) + 1)) + 140*sqrt(2)*a^3*sin(3/2
*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) + 1)) + (-60*I*sqrt(2)*a^3*cos(2*d*x + 2*c)^2 - 60*I*sqrt(2)*a^3*s
in(2*d*x + 2*c)^2 - 120*I*sqrt(2)*a^3*cos(2*d*x + 2*c) - 60*I*sqrt(2)*a^3)*cos(7/2*arctan2(sin(2*d*x + 2*c), c
os(2*d*x + 2*c) + 1)) + 60*(sqrt(2)*a^3*cos(2*d*x + 2*c)^2 + sqrt(2)*a^3*sin(2*d*x + 2*c)^2 + 2*sqrt(2)*a^3*co
s(2*d*x + 2*c) + sqrt(2)*a^3)*sin(7/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) + 1)))*(cos(2*d*x + 2*c)^2 +
sin(2*d*x + 2*c)^2 + 2*cos(2*d*x + 2*c) + 1)^(3/4)*sqrt(a) + (-420*I*sqrt(2)*a^3*cos(1/2*arctan2(sin(2*d*x + 2
*c), cos(2*d*x + 2*c) + 1)) + 420*sqrt(2)*a^3*sin(1/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) + 1)) + (-84*
I*sqrt(2)*a^3*cos(2*d*x + 2*c)^2 - 84*I*sqrt(2)*a^3*sin(2*d*x + 2*c)^2 - 168*I*sqrt(2)*a^3*cos(2*d*x + 2*c) -
84*I*sqrt(2)*a^3)*cos(5/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) + 1)) + 84*(sqrt(2)*a^3*cos(2*d*x + 2*c)^
2 + sqrt(2)*a^3*sin(2*d*x + 2*c)^2 + 2*sqrt(2)*a^3*cos(2*d*x + 2*c) + sqrt(2)*a^3)*sin(5/2*arctan2(sin(2*d*x +
2*c), cos(2*d*x + 2*c) + 1)))*(cos(2*d*x + 2*c)^2 + sin(2*d*x + 2*c)^2 + 2*cos(2*d*x + 2*c) + 1)^(1/4)*sqrt(a
) - (210*sqrt(2)*a^3*arctan2((cos(2*d*x + 2*c)^2 + sin(2*d*x + 2*c)^2 + 2*cos(2*d*x + 2*c) + 1)^(1/4)*sin(1/2*
arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) + 1)), (cos(2*d*x + 2*c)^2 + sin(2*d*x + 2*c)^2 + 2*cos(2*d*x + 2*c
) + 1)^(1/4)*cos(1/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) + 1)) + 1) - 210*sqrt(2)*a^3*arctan2((cos(2*d*
x + 2*c)^2 + sin(2*d*x + 2*c)^2 + 2*cos(2*d*x + 2*c) + 1)^(1/4)*sin(1/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x +
2*c) + 1)), (cos(2*d*x + 2*c)^2 + sin(2*d*x + 2*c)^2 + 2*cos(2*d*x + 2*c) + 1)^(1/4)*cos(1/2*arctan2(sin(2*d*x
+ 2*c), cos(2*d*x + 2*c) + 1)) - 1) - 105*I*sqrt(2)*a^3*log(sqrt(cos(2*d*x + 2*c)^2 + sin(2*d*x + 2*c)^2 + 2*
cos(2*d*x + 2*c) + 1)*cos(1/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) + 1))^2 + sqrt(cos(2*d*x + 2*c)^2 + s
in(2*d*x + 2*c)^2 + 2*cos(2*d*x + 2*c) + 1)*sin(1/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) + 1))^2 + 2*(co
s(2*d*x + 2*c)^2 + sin(2*d*x + 2*c)^2 + 2*cos(2*d*x + 2*c) + 1)^(1/4)*cos(1/2*arctan2(sin(2*d*x + 2*c), cos(2*
d*x + 2*c) + 1)) + 1) + 105*I*sqrt(2)*a^3*log(sqrt(cos(2*d*x + 2*c)^2 + sin(2*d*x + 2*c)^2 + 2*cos(2*d*x + 2*c
) + 1)*cos(1/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) + 1))^2 + sqrt(cos(2*d*x + 2*c)^2 + sin(2*d*x + 2*c)
^2 + 2*cos(2*d*x + 2*c) + 1)*sin(1/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) + 1))^2 - 2*(cos(2*d*x + 2*c)^
2 + sin(2*d*x + 2*c)^2 + 2*cos(2*d*x + 2*c) + 1)^(1/4)*cos(1/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) + 1)
) + 1))*sqrt(a))/d

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int {\cos \left (c+d\,x\right )}^7\,{\left (a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}\right )}^{7/2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(c + d*x)^7*(a + a*tan(c + d*x)*1i)^(7/2),x)

[Out]

int(cos(c + d*x)^7*(a + a*tan(c + d*x)*1i)^(7/2), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)**7*(a+I*a*tan(d*x+c))**(7/2),x)

[Out]

Timed out

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